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A projectile fired with initial velocity...

A projectile fired with initial velocity u at some angle `theta` has a range R . If the initial velocity be doubled at the same angle of projection, then the range will be

A

2R

B

R/2

C

R

D

4R

Text Solution

Verified by Experts

The correct Answer is:
D
`R = (u^(2) sin 2theta)/g : R prop u^(2)`
`R_(1)/R_(2) = u^(2)/(4u^(2)) rArr R_(2) = 4R_(1)`
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