A particle covers 50 m distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed

Options

A. 100 m
B. 150 m
C. 200 m
D. 250 m

Answer

C

Explanation

`R = (u^(2) sin 2theta)/g : R prop u^(2)`
`R_(1)/R_(2) = u^(2)/(2u)^(2) rArr R_(2) = 4R_(1) = 4 xx 50 = 200 m`