Ratio between maximum range and square of time of flight in projectile motion is

Options

A. `10 : 49`
B. `49 :10`
C. `98:10`
D. `10:98`

Answer

B

Explanation

For maximum range `theta = 45^(@)`
`R_("max") = u^(2)/g`
`T^(2) = ((2u sin theta)/g)^(2) = (4u^(2) sin^(2) theta)/g^(2) = (4u^(2))/g^(2) xx 1/2`
`u^(2)/g xx g^(2)/(2u^(2)) = 9.8/2 = 4.9 = 49/10 = 49 : 10`