A body is projected from the ground with a velocity `v = (3hati +10 hatj)ms^(-1)`. The maximum height attained and the range of the body respectively are (given `g = 10 ms^(-2))`

Options

A. 5 m and 6 m
B. 3 m and 10 m
C. 6m and 5 m
D. 3 m and 5 m

Answer

A

Explanation

`v = 3hati + 10 hatj`
`v_(x) = 3, v_(y) = 10`
`H = v_(y)^(2)/(2g) = 100/20 = 5m`
`R = v_(x) xx T = v_(x) xx (2v_(g))/g = 3 xx (2 xx 10)/10 = 6 m`