Two bodies are thrown up at angles of `45^(@)` and `60^(@)`, respectively, with the horizontal. If both bodies attain same vertical height, then the ratio of velocities with which these are thrown is

Options

A. `sqrt(2/3)`
B. `2/sqrt(3)`
C. `sqrt(3/2)`
D. `sqrt(3)/2`

Answer

C

Explanation

`H = (u^(2) sin^(2) theta)/(2g)`
Since, `H_(1) = H_(2) rArr (u_(1)^(2) sin^(2) 45^(@))/(2g) = (u_(2)^(2) sin^(2) 60)/(2g)`
`rArr (3/4 xx 2/1) rArr u_(1)/u_(2) = sqrt(3/2)`