A projectile is fired at an angle of `45^(@)` with the horizontal. Elevation angle of the projection at its highest point as seen from the point of projection is

Options

A. `tan^(-1)(sqrt(3)/2)`
B. `45^(@)`
C. `60^(@)`
D. `tan^(-1)1/2`

Answer

D

Explanation

`tan alpha = H/(R//2) = (u^(2)/(4g))/(u^(2)/(2g)) = 1/2`
`rArr alpha = tan^(-1) (1/2)`