An object is projected with a velocity of `20(m)/(s)` making an angle of `45^@` with horizontal. The equation for the trajectory is `h=Ax-Bx^2` where h is height, x is horizontal distance, A and B are constants. The ratio A:B is (g`=ms^-2)`

Options

A. `1:5`
B. `5:1`
C. `1:40`
D. `40:1`

Answer

D

Explanation

`h = Ax - Bx^(2)`
Since, `h = x tan theta - 1/2 (gx^(2) (1 + tan^(2) theta))/u^(2)`
`A = tan theta = 1, B = (10 xx 2)/(2 xx 400) = 1/40`
`A/B = 40`