The equations of motion of a projectile are given by `x=36tm` and `2y=96t-9.8t^(2)m` .The angle of projection is

Options

A. `sin^(-1)(4/5)`
B. `sin^(-1)(3/5)`
C. `sin^(-1)(4/3)`
D. `sin^(-1)(3/4)`

Answer

A

Explanation

`x = 36 t` and `2y = 96t - 9.8 t^(2)`
`v_(x) =(dx)/(dt) = 36` and `(dy)/(dt) = 48 - 9.8 t`
`t =0, u_(x) = 36` and `u_(y) = 48`
`tan theta = u_(y)/u_(x) = 48/36 = 4/3`
`sin theta 4/5 rArr theta = sin^(-1) (4/5)`