A car is moving along a straight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is `mu` , the shortest distance in which the car can be stopped is

Options

A. `(v_(0)^(2))/(2 mu g)`
B. `(v_(0))/(mu g)`
C. `((v_(0))/(mu g))^(2)`
D. `(v_(0))/(mu)`

Answer

A

Explanation

Retarding force = ma = `mu N = mu mg`
`implies a = mu g`
Stopping distance (S) = `(u^(2))/(2a) = (v_(0)^(2))/(2 mu g)`