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A child weighing 25 kg slides down a rop...

A child weighing 25 kg slides down a rope hanging from the branch of a tall tree. If the force of friction acting against him is 2 N , what is the acceleration of the child

A

`22.5 m//s^(2)`

B

`8 m//s^(2)`

C

`5 m//s^(2)`

D

`9.72 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

Neto downward force = Weight - Friction
ma = `25 xx 9.8 -2`
`implies a = (25 xx 9.8 -2)/(25) = 9.72 m//s^(2)`
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