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In the figure given, the system is in eq...

In the figure given, the system is in equilibrium. What is the maximum value that W can have if the friction force on the 40N block can not exceed 12.0N?

A

3.45 N

B

6.92 N

C

10.35 N

D

12.32 N

Text Solution

Verified by Experts

The correct Answer is:
B
T = cos `30^(@) = 12`
`implies T = (24)/(sqrt3) N`

`T sin 30^(@) = W`
`implies W = (24)/(sqrt3) xx (1)/(2) = (12)/(sqrt3) = 6.92 N`
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