A vehicle of mass `m` is moving on a rough horizontal road with momentum `P` . If the coefficient of friction between the tyres and the road be `mu`, then the stopping distance is:

Options

A. `(P)/(2 mu mg )`
B. `(p^(2))/(2 mu mg)`
C. `(p)/(2 mu m^(2) g)`
D. `(p^(2))/(2 mu m^(2) g)`

Answer

D

Explanation

`P = mv implies v = (P)/(m) ` and `a = mu g`
Stoppingn distance (S) = `(v^(2))/(2a) = (((p^2)/(m^2)))/(2 mu g) = (p^(2))/(2 mu m^(2) g)`