Three bricks each of length L and mass M are arranged as shown from the wall. The distance of the centre of mass of the system from the wall is

Options

A. L/4
B. L/2
C. (3/2) L
D. (11/12L)

Answer

D

Explanation

`m_(1)= m_(2) = m_(3) = M`
`x_(1) = L//2, x_(2)= L, x_(3)= L + (L)/(4)= (5L)/(4)`
`x_(CM)= (m_(1) x_(1) + m_(2) x_(2) + m_(3)x_(3))/(m_(1) + m_(2) + m_(3))`
`= (M xx ((L)/(2) + L + (5L)/(4)))/(3M)= (11L)/(12)`