Five particles of mass 2 kg each are attached to the rim of a circular disc of radius 0.1 m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is

Options

A. `1kg -m^(2)`
B. `0.1 kg -m^(2)`
C. `2 kg -m^(2)`
D. `0.2 kg -m^(2)`

Answer

B

Explanation

`I= Sigma mr^(2)= 5mr^(2)= 5 xx 2 xx (0.1)^(2)= 0.1 kg m^(2)`