Four small objects each of mass m are fixed at the corners of a rectangular wire-frame of negligible mass and of sides a and b (a > b) . If the wire frame is now rotated about an axis passing along the side of length then the moment of inertia of the system for this axis of rotation is:

Options

A. `2ma^(2)`
B. `4ma^(2)`
C. `2m(a^(2)+b^(2))`
D. `2m(a^(2)-b^(2))`

Answer

C

Explanation

`I= 2ma^(2) + 2mb^(2)`
`=2m (a^(2) + b^(2))`