A solid cylinder of mass 20kg has length 1 m and radius 0.2 m. Then its moment of inertia (in kg-`m^(2)`) about its geometrical axis is :

Options

A. `M((L^(2))/(12) + (R^(2))/(4))`
B. `(ML^(2))/(4)`
C. `(1)/(2) MR^(2)`
D. `(3)/(2) MR^(2)`

Answer

D

Explanation

`I= I_(CM) + MR^(2)`
`I= (MR^(2))/(2) + MR^(2)`
`rArr (3)/(2) MR^(2)`