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Three rings each of mass M and radius R ...

Three rings each of mass M and radius R are arranged as shown in the figure. The moment of inertia of the system about YY¢ will be

A

`3MR^(2)`

B

`(3)/(2) MR^(2)`

C

`5MR^(2)`

D

`(7)/(2) MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`I= I_(1) + I_(2) + I_(3)`
`rArr (MR^(2))/(2) + (3MR^(2))/(2) + (3MR^(2))/(2)`
`rArr (7MR^(2))/(2)`
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