A torque of 30 N-m is acting on a wheel of mass 5 kg and moment of inertia `2 kg-m​^(2)`​. If wheel starts rotating from rest then its angular displacement in 10 seconds will be-

Options

A. 750 rad
B. 1500 rad
C. 3000 rad
D. 6000 rad

Answer

A

Explanation

`alpha= (tau)/(I)= (30)/(2)= 15` rad/`sec^(2)`
`theta= omega_(0) t+ (1)/(2) alpha t^(2)= 0 + (1)/(2) xx 15 xx (10)^(2)= 750` rad