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The instantaneous angular position of a ...

The instantaneous angular position of a point on a rotating wheel is given by the equation
`theta(t) = 2t^(3) - 6 t^(2)`
The torque on the wheel becomes zero at

A

t=2s

B

t=1s

C

1= 0.2s

D

t= 0.25s

Text Solution

Verified by Experts

The correct Answer is:
B
`theta (t)= 2t^(3) - 6t^(2)`
`rArr omega= (d theta)/(dt)= 6t^(2)- 12t rArr alpha= (d omega)/(dt)= 12 t- 12`
`alpha= 0 rArr t=1` sec
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