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A rod of weight w is supported by two pa...

A rod of weight `w` is supported by two parallel knife edges `A` and `B` and is in equilibrium in a horizontal position. The knives are at a distance `d` from each other. The centre of mass of the rod is at a distance `x` from `A`.

A

`(Wd)/(x)`

B

`(W(d-x))/(x)`

C

`(W(d-x))/(d)`

D

`(Wx)/(d)`

Text Solution

Verified by Experts

The correct Answer is:
C
`N_(A) + N_(B) = mg = W`
`N_(A) x= N_(B) (d-x)`
`rArr N_(A) x= (mg- N_(A)) (d-x)`
`rArr N_(A) x= W (d-x) - N_(A) (d- x)`
`rArr N_(A) d= W (d-x) rArr N_(A) = (W (d-x))/(d)`
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