A solid sphere (mass 2M) and a thin spherical shell (mass M) both of the same size roll down an inclined plane, then:

Options

A. Solid sphere will reach the bottom first
B. Hollow spherical shell will reach the bottom first
C. Both will reach at the same time
D. None of these

Answer

A

Explanation

Time of descent `t= (1)/(sin theta) sqrt((2h)/(g) (1+ (K^(2))/(R^(2))))` For solid sphere `(K^(2))/(R^(2))= (2)/(5)`
For hollow sphere, `(K^(2))/(R^(2))= (2)/(3)`
Solid sphere will take less time so it will reach the bottom first.