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A steal wire of cross-section area 3xx10...

A steal wire of cross-section area `3xx10^(-6) m^(2)` can withstand a maximum strain of `10^(-3)` .Young's modulus of steel is `2xx10^(11) Nm^(-2)` .The maximum mass this wire can hold is

A

40 kg

B

60 kg

C

80 kg

D

100 kg

Text Solution

Verified by Experts

The correct Answer is:
B
`A= 3 xx 10^(-6) m^(2), ("Strain")_("max") = 10^(-3), Y= 2 xx 10^(11)`
`Y= ("Stress")/("Strain") rArr` Max. strain `= ("Max. stress")/(Y)= (mg//A)/(Y)`
`m= (Y xx "strain " xx A)/(g)= (2 xx 10^(11) xx 10^(-3) xx 3 xx 10^(-6))/(10)= 60 kg`
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