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A bob of mass 10 kg is attached to wire ...

A bob of mass 10 kg is attached to wire 0.3 m long. Its breaking stress is `4.8 xx 10^(7) N//m^(2)`. The area of cross section of the wire is `10^(-6) m^(2)`. The maximum angular velocity with which it can be rotated in a horizontal circle

A

8 rad/sec

B

4 rad/sec

C

2 rad/sec

D

1 rad/sec

Text Solution

Verified by Experts

The correct Answer is:
B
Centripetal force = Breaking force
`rArr m omega^(2) r`= breaking stress `xx` cross sectional area
`rArr m omega^(2) r= P xx A rArr omega = sqrt((P xx A)/(mr))= sqrt((4. xx 10^(7) xx 10^(-6))/(10 xx 0.3))`
`omega= 4` rad/sec
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