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The work per unit volume to stretch the ...

The work per unit volume to stretch the length by `1%` of a wire with cross sectional area of `1mm^2` will be. `[Y=9xx10^(11)N//m^2]`

A

`9 xx 10^(11)J`

B

`4.5 xx 10^(7) J`

C

`9 xx 10^(7) J`

D

`4.5 xx 10^(11)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`U= (1)/(2) xx Y xx("Strain")^(2) = (9)/(2) xx 10^(11) xx ((1)/(100))^(2)= 4.5 xx 10^(7) J`
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