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K is the force constant of a spring. The...

K is the force constant of a spring. The work done in increasing its extension from `l_(1)` to `l_(2)` will be

A

`K (l_(2)- l_(1))`

B

`(K)/(2) (l_(2) + l_(2))`

C

`K (l_(2)^(2)- l_(1)^(2))`

D

`(K)/(2) (l_(2)^(2)- l_(1)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
`U_(1)= (1)/(2) Kl_(1)^(2), U_(f)= (1)/(2) Kl_(2)^(2)`
`Delta U= (1)/(2) K (l_(2)^(2)- l_(1)^(2))`
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