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The angle turned by a body undergoing ci...

The angle turned by a body undergoing circular motion depends on time as `theta = theta_(0)+theta_(1)t+theta_(2)t^(2)`. Then the angular acceleration of the body is

A

`theta_(1)`

B

`theta_(2)`

C

`2theta_(1)`

D

`2theta_(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Angular acceleration = `(d^(2)theta)/(dt^(2))=2theta_(2)`
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