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A sphere of mass 10 kg and radius 0.5 m ...

A sphere of mass 10 kg and radius 0.5 m rotates about a tangent. The moment of inertia of the solid sphere about tangent is

A

`5"kg-m"^(2)`

B

`2.7"kg-m"^(2)`

C

`3.5"kg-m"^(2)`

D

`4.5"kg-m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`I=I_(CM)+MR^(2)=(2)/(5)MR^(2)+MR^(2)=(7)/(5)MR^(2)`
`I=(7)/(5)xx10xx(0.5)^(2)=3.5"kg-m"^(2)`
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