Find the out the moment of inertia of a ring having uniform mass distribution of mass `M` and radius `R` about an axis which is tangent ot the ring and (`a`) in the plane of the ring (`b`). perpendicular to the plane of the ring.

Options

A. `2Mr^(2)`
B. `3//2Mr^(2)`
C. `Mr^(2)`
D. `1//2Mr^(2)`

Answer

B

Explanation

MOI about diameter of ring
`I.=(Mr^(2))/(2)`
MOI about tangent
`I=(Mr^(2))/(2)+Mr^(2)=(3)/(2)Mr^(2)`