Two rods each of mass m and length 1 are joined at the centre to form a cross. The moment of inertia of this cross about an axis passing through the common centre of the rods and perpendicular to the plane formed by them, is :

Options

A. `ml^(2)//12`
B. `ml^(2)//6`
C. `ml^(2)//3`
D. `ml^(2)//2`

Answer

B

Explanation

`I=(ml^(2))/(12)+(ml^(2))/(12)=(ml^(2))/(6)`