The moment of inertia of a thin uniform rod of mass `M` and length `L` about an axis passing through its mid-point and perpendicular to its length is`I_0`. Its moment of inertia about an axis passing through one of its ends perpendicular to its length is.

Options

A. `I_(0)+ML^(2)`
B. `I_(0)+(ML^(2))/(2)`
C. `I_(0)+(ML^(2))/(4)`
D. `I_(0)+2ML^(2)`

Answer

C

Explanation

`I_(0)=(ML^(2))/(12)`
`I=I_(0)+M((L)/(2))^(2)=I_(0)+(ML^(2))/(4)`