Four particles each of mass `m` are placed at the corners of a square of side length `l`. The radius of gyration of the system about an axis perpendicular to the plane of square and passing through its centre is

Options

A. `(l)/(sqrt(2))`
B. `(l)/(2)`
C. l
D. `(sqrt(2))l`

Answer

A

Explanation

`I=4m((1)/(sqrt(2)))^(2)=2ml^(2)`
Now, `2ml^(2)=4mK^(2)`
implies `K=(l)/(sqrt(2))`