Four spheres of diameter 2a and mass M are placed with their centres on the four corners of a square of side b. Then moment of inertia of the system about an axis about one of the sides of the square is :-

Options

A. `(4)/(5)Ma^(2)+2Mb^(2)`
B. `(8)/(5)Ma^(2)+2Mb^(2)`
C. `(8)/(5)Ma^(2)`
D. `(4)/(5)Ma^(2)+4Mb^(2)`

Answer

B

Explanation

`I=((2)/(5)Ma^(2))xx2+((2)/(5)Ma^(2))xx2+2Mb^(2)`
= `(8)/(5)Ma^(2)+2Mb^(2)`