An iceberg of density `900kg//m^(3)` is floating in water of density `1000 kg//m^(3)`. The percentage of volume of ice cube outside the water is

Options

A. 0.2
B. 0.35
C. 0.1
D. 0.25

Answer

C

Explanation

`rho_l gV_("in")=V rho_s g`
`implies V_("in")=((rho_s)/(rho_l))V`
`V_("out")=V-V_("in")`
`=V[1-(rho_s)/(rho_l)]=V[1-(900)/(1000)]=(V)/(10)=0.1 V`
10% of original volume.