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A large tank filled with water to a height `h` is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from h to `(h)/(2)` and from `(h)/(2)` to zero is

A

`sqrt2`

B

`1/sqrt2`

C

`sqrt2-1`

D

`(1)/(sqrt2-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

Time taken for the level to fall from H to H. -
`t= (A)/(A_0)sqrt(2/g)(sqrt(H)-sqrt(H.))`
`(t_1)/(t_2)=(sqrt(h)-sqrt(h/2))/(sqrt(h/2)-0)=(1-1/sqrt2)/(1/sqrt2)=sqrt2 -1`
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