The water flows form a tap of diameter `1.25` cm with a rate of `5xx10^(-5) m^(3) s^(-1).` The density and coefficient of viscosity of water are `10^(3)kg m ^(-3) and 10^(-3)` Pa. s respectively. The flow of water is

Options

A. Steady with Reynolds number 5100
B. Turbulent with Reynolds number 5100
C. Steady with Reynolds number 3900
D. Turbulent with Reynolds number 3900

Answer

B

Explanation

`N_R=(v rho D)/(eta)" "`…(i)
Now, `Q=(pi D^2)/(4)xx v implies v=(4Q)/(pi D^2)" "`…(ii)
By eq. (i) and (ii) `N_R=(4Q rho)/(pi D eta)`
`implies (4xx5xx10^(-5)xx10^(3))/(3.14xx1.25xx10^(-2)xx10^(-3))=5095 ~~ 5100` (Approx.)
`N_R gt 3000` (turbulent)