The cylinderical tube of a spray pump has radius R, One end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is :

Options

A. `(VR^2)/(nr^2)`
B. `(VR^2)/(n^3 r^2)`
C. `(V^2R)/(nr)`
D. `(VR^2)/(n^2r^2)`

Answer

A

Explanation

`A_1 v_1=A_2 v_2`
`implies pi R^2 V = n pi r^2 v. implies (R^2 V)/(n r^2)`.