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Two coils have a mutual inductance 0.005...

Two coils have a mutual inductance 0.005 H, The current changes in the first coil according to the equation `i= i_(m) sin omega t` where `i_(m) = 10 A` and `omega= 100pi rad s^(-1)`. The maximum value of the emf induced in the second coil is

A

`5pi`

B

`4pi`

C

`2pi`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
A
`|e|=M(di)/dt=Mi_(m)omegacosomegat`
`thereforee_(0)=0.005xx10xx100pi=5pi`Volt.
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