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Two circuits have coefficient of mutual induction of `0.09` henry. Average e.m.f. induced in the secondary by a change of current from `0` to `20` ampere in `0.006` second in the primary will be

A

120 V

B

80 V

C

200 V

D

300 V

Text Solution

Verified by Experts

The correct Answer is:
D
`|e|=M(di)/dt=0.09xx20/0.006=300`Volt.
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