The circuit shown consists of a switch (S), a battery (B) of emf E, a resistance R, and an inductor L.

The current in the circuit at the instant the switch is closed is-

Options

A. E/R
B. `E//R(1-e)`
C. `prop`
D. 0

Answer

D

Explanation

Using the equation `I=I_(0)(1-e^((-t)/tau))`,
Put t = 0 we get I = 0, just when the battery is closed inductor provides infinite resistance to the current flow
`therefore` Current is zero initially.