If the binding energy per nucleon in L i...

If the binding energy per nucleon in `L i^7` and `He^4` nuclei are respectively `5.60 MeV` and `7.06 MeV`. Then energy of reaction `L i^7 + p rarr 2_2 He^4` is.

19.6 MeV

2.4 MeV

8.4 MeV

17.3 MeV

Text Solution

Verified by Experts

The correct Answer is:

Energy of reaction
`Q= 2 xx 4 xx 7.06 - 7 xx 5.6 = 17.28MeV= 17.3 MeV`

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