The gravitational force between a H-atom and another particle of mass m will be given by Newton's law
`F=G(M.m)/(r^(2))` where r is in m and

Options

A. `M = m_("proton") + m_("electron")`
B. `M= m_("proton") + m_("electron") - (B)/(c^(2) (B= 13.6eV)`
C. M is not relate to the mass of the hydrogen atom
D. `M= m_("proton") + m_("electron") - (|V|)/(c^(2))` (`|V|`= magnitude of the potential energy of electron in the H-atom)

Answer

B

Explanation

Given `F= (GM m)/(r^(2))`
M = Effective mass of hydrogen atom
= Mass of electron + Mass of proton `- (B)/(c^(2))` where B is BE of hydrogen atom = 13 6. eV