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Assume that a neutron breaks into a prot...

Assume that a neutron breaks into a proton and an electron. The energy released during this process is (mass of neutron = `1.6725 xx 10^(-27)` kg, mass of proton = `1.6725 xx 10^(-27) kg`, mass of electron `= 9 xx 10^(-31) kg)`

A

`0.06%`

B

`0.0006%`

C

`0.02%`

D

`0.00%`

Text Solution

Verified by Experts

The correct Answer is:
A

Use `Delta E= Delta mc^(2)`
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Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron = 1.6725 xx 10^(-27) kg mass of proton = 1.6725 xx 10^(-27) kg mass of electron = 9 xx 10^(-31) kg )

A neutron breaks into a proton and electron. Calculate the energy produced in this reaction in MeV. Mass of an electron =9xx10^(-11) kg. mass of proton=1.6725xx 10^(-27) kg, Mass of neutron=1.6747 xx10^(-27) kg. speed of light = 3xx10^(8)m//sec .

A neutron break into proton and electron. Calculate the energy produced in this reactions in MeV. ( m_e=9.1xx10^(-31)kg, m_p=1.6725xx10^(-27) kg , m_n=1.6747xx10^(-27) kg ) :-

The mass of 1 mole of neutrons (m_(n) = 1.675 xx 10^(-27) kg) is:

A neutron breaks into a proton and electorn. Calculate the eenrgy produced in this reaction in m_(e) = 9 xx 10^(-31) kg, m_(p) = 1.6725 xx 10^(-27) kg, m_(n) = 1.6747 xx 10^(-27) kg, c = 3xx10^(8)m//sec .

Calculate the equivalent energy of electrons and proton at rest. Given that mass of electron =9.1xx10^(-31)kg and mass of proton =1.673xx10^(-27)kg .

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