An atomic power nuclear reactor can deliver `300 MW`. The energy released due to fission of each nucleus of uranium atom `U^238` is `170 MeV`. The number of uranium atoms fissioned per hour will be.

Options

A. `30 xx 10^(25)`
B. `4 xx 10^(22)`
C. `10 xx 10^(20)`
D. `5 xx 10^(15)`

Answer

B

Explanation

No. of uranium atom fissioned per hour `= (P)/(E)`
`= (300 xx 10^(6))/(170 xx 10^(6) xx 1.6 xx 10^(-19)) xx 3600`
`=3.97 xx 10^(22) = 4 xx 10^(22)`