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what is the missing particle or nuclide in the box `square`, in the following nuclear reaction ?
`""_7N^14 (square P) ""_6C^14` ?

A

`S^(32), F^(19), ""_(0)n^(1)`

B

`F^(19), S^(32), ""_(0)n^(1)`

C

`Be^(9), F^(19), ""_(0)n^(1)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
(i) `""_(16)S^(32) + ""_(0)n^(1) rarr ""_(15)P^(32) + ""_(1)H^(1)`
(ii) `""_(9)F^(19) + ""_(1)H^(1) rarr ""_(2)He^(4) + ""_(8)O^(16)`
(iii) `""_(7)N^(14) + ""_(0)n^(1) rarr ""_(6)C^(14) + ""_(1)H^(1)`
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