If `200 MeV` energy is released in the fission of a single `U^235` nucleus, the number of fissions required per second to produce `1` kilowatt power shall be (Given `1 eV = 1.6 xx 10^-19 J`).

Options

A. `3.125 xx 10^(13)`
B. `3.125 xx 10^(14)`
C. `3.125 xx 10^(15)`
D. `3.125 xx 10^(16)`

Answer

A

Explanation

`(P)/(E)= ((n)/(t)) rArr (n)/(t)= (1000)/(200 xx 10^(6) xx 1.6 xx 10^(-19))`
`rArr (n)/(t)= 3.125 xx 10^(13)`