Given below are three schematic graphs of potential energy V(r) versus distance r for three atomic particles : electron `(e^(-))`, proton `(p^(+))` and neutron (n), in the presence of a nucleus at the origin O. The radius of the nucleus is `r_(0)`. The scale on the V-axis may not be the same for all figures. The correct pairing of each graph with the corresponding atomic particle is -

Options

A. `(1, n), (2, p^(+)), (3,e)`
B. `(1, p^(+)), (2,e), (3, n)`
C. `(1, e), (2, p^(+)), (3, n)`
D. `(1, p^(+)), (2,n) (3,e)`

Answer

A

Explanation

Outside the nucleus electric potential decreases Since, electron is negativity changed.
`therefore` Its PE is −ve even outside the nucleus. Where Nucleus attractive force is negligible. `(3) rarr e`
Outside the nucleus neutron will not experience electric force as it is neutral. So, no PE associated with it outside nucleus `(1) rarr` Neutron