A sample contains `16 gm` of radioactive material, the half-life of which is two days. After `32` days, the amount of radioactive material left in the sample is

Options

A. Less than 1 mg
B. `(1)/(4)g`
C. `(1)/(2)g`
D. 1g

Answer

A

Explanation

Number of nuclei remaining
`= (N_(0))/(2^(n)) [n= (32)/(2)= 16]`
`= (16)/(2^(16))= (2^(4))/(2^(16)) = (1)/(2^(12))`
Hence, `(1)/(2^(12)) lt 1mg`