The decay constant of a radioactive sample is `lambda`. The half-life and mean life of the sample respectively are

Options

A. `(1)/(lamda) and (log_(e)2)/(lamda)`
B. `(log_(e)2)/(lamda) and (1)/(lamda)`
C. `lamda log_(e)2 and (1)/(lamda)`
D. `(lamda)/(log_(e)2) and (1)/(lamda)`

Answer

B

Explanation

`T_((1)/(2))= (ln 2)/(lamda)= (log_(e)2)/(lamda) rArr tau= (1)/(lamda)`