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What is the respective number of alpha a...

What is the respective number of `alpha` and `beta` particles emitted in the following radioactive decay? `._(90)X^(200) rarr ._(80)Y^(168)`

A

6 and 8

B

8 and 8

C

6 and 6

D

8 and 6

Text Solution

Verified by Experts

The correct Answer is:
D
`n_(alpha)= (A- A.)/(4)= (200- 168)/(4)= 8`
`n_(beta) = 2n_(alpha)- Z + Z.= 2 xx 8 - 90 + 80= 6`
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