The weight of an object in the coal mine...

The weight of an object in the coal mine, sea level and at the top of the mountain are `W_(1),W_(2)` and `W_(3)` respectively, then

`W_1ltW_2gtW_3`

`W_1=W_2=W_3`

`W_1ltW_2ltW_3`

`W_1gtW_2gtW_3`

Text Solution

Verified by Experts

The correct Answer is:

At mountain, `g_h=g/((1+h/R)^2)`
At Sea level, `g_s=g`
At Coal mine, `g_d=g(1-d/R)`

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